Question

Using the equation `2"Al"(s) + 3"H"_2"SO"_4(aq) -> "Al"_2("SO"_4)_3(aq) + 3"H"_2(g)`. Starting with `15.0` moles of `"Al"`, determine the theoretical yield of `"H"_2` ?

Answer 1

`"22.5 moles H"_2`

Explanation:

You first find the ratio between your unknown and your known, unknown on top and known on the bottom.

So with this question, your unknown is `"H"_2` and your known is `"Al"`. Your ratio is `3/2`.

Then, you take the number of moles of your known, `15` moles of `"Al"`, and multiply it by that ratio and you get the number of moles of your unknown, which in this case is `22.5` moles of `"H"_2`

`"15 mol Al" * "3 mol H"_2/"2 mol Al" = "22.5 mol H"_2`