What are common mistakes students make with respect to extraneous solutions?

1 Answer
Aug 5, 2017

A couple of thoughts...

Explanation:

These are more guesses than informed opinion, but I would suspect the main error is along the lines of not checking for extraneous solutions in the following two cases:

  • When solving the original problem has involved squaring it somewhere along the line.

  • When solving a rational equation and having multipled both sides by some factor (which happens to be zero for one of the roots of the derived equation).

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Example 1 - Squaring

Given:

sqrt(x+3) = x-3

Square both sides to get:

x+3 = x^2-6x+9

Subtract x+3 from both sides to get:

0 = x^2-7x+6 = (x-1)(x-6)

Hence x=1 or x=6" " (but x=1 is not a valid solution of the original equation)

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Example 2 - Rational equation

Given:

x^2/(x-1) = (3x-2)/(x-1)

Multiply both sides by (x-1) to get:

x^2 = 3x-2

Subtract 3x-2 from both sides to get:

0 = x^2-3x+2 = (x-1)(x-2)

Hence x=1 or x=2" " (but x=1 is not a valid solution of the original equation)