What are the absolute extrema of f(x)= 2 + x^2 in [-2, 3]? Calculus Graphing with the First Derivative Identifying Turning Points (Local Extrema) for a Function 1 Answer Alan N. ยท Anjali G Mar 5, 2017 f(x) has an absolute minimum of 2 at x=0 Explanation: f(x)= 2+x^2 f(x) is a parabola with a single absolute minimum where f'(x)=0 f'(x) =0+2x = 0 -> x=0 :.f_min(x) = f(0) = 2 This can be seen on the graph of f(x) below: graph{2+x^2 [-9.19, 8.59, -0.97, 7.926]} Answer link Related questions How do you find the x coordinates of the turning points of the function? How do you find the turning points of a cubic function? How many turning points can a cubic function have? How do you find the coordinates of the local extrema of the function? How do you find the local extrema of a function? How many local extrema can a cubic function have? How do I find the maximum and minimum values of the function f(x) = x - 2 sin (x) on the... If f(x)=(x^2+36)/(2x), 1 <=x<=12, at what point is f(x) at a minimum? How do you find the maximum of f(x) = 2sin(x^2)? How do you find a local minimum of a graph using the first derivative? See all questions in Identifying Turning Points (Local Extrema) for a Function Impact of this question 2019 views around the world You can reuse this answer Creative Commons License