What are the exact solutions of $x^2 − 3x − 7 = 0$ ?

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Answer 1 · 2016-11-13T14:02:56

4.54 and -1.54

$x^2-3x-7=0$

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Here

$a=+1$

$b=-3$

$c=-7$

$x={-(-3)+-sqrt[(-3)^2-4times(1)times(-7)]}/(2times(-1))$

After solving we get

$x={3+sqrt(37)}/(2)$ and $x={3-sqrt(37)}/2$

Therefore $x=4.54 and x=-1.54$

What are the exact solutions of x^2 − 3x − 7 = 0x^2 − 3x − 7 = 0?