What are the extrema of f(x) = 8 - 2x for x>=6? Calculus Graphing with the First Derivative Identifying Turning Points (Local Extrema) for a Function 1 Answer Anjali G Nov 13, 2016 f(x) is a line with a negative slope, so on the interval x>= 6, the maximum is at x=6. There is no minimum because f(x) is always decreasing, and the interval given is [6,oo]. graph{-2x+8 [-4.25, 15.75, -7.8, 2.2]} Answer link Related questions How do you find the x coordinates of the turning points of the function? How do you find the turning points of a cubic function? How many turning points can a cubic function have? How do you find the coordinates of the local extrema of the function? How do you find the local extrema of a function? How many local extrema can a cubic function have? How do I find the maximum and minimum values of the function f(x) = x - 2 sin (x) on the... If f(x)=(x^2+36)/(2x), 1 <=x<=12, at what point is f(x) at a minimum? How do you find the maximum of f(x) = 2sin(x^2)? How do you find a local minimum of a graph using the first derivative? See all questions in Identifying Turning Points (Local Extrema) for a Function Impact of this question 1740 views around the world You can reuse this answer Creative Commons License