What are the factors of #2m^3+3m^2+4m+6#?

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Answer 1 · 2014-11-09T17:12:57

#2m^3+3m^2+4m+6#

by factoring #m^2# out of the first two terms and #2# out of the last two terms,

#=m^2(2m+3)+2(2m+3)#

by factoring out #2m+3#,

#=(m^2+2)(2m+3)#

Hence, its factors are #(m^2+2)# and #(2m+3)#.

I hope that this was helpful.