What are the intercepts for y=2x^2-10x-1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer ali ergin Apr 21, 2016 y=-1 x_1=0,098 x_2=5,098 Explanation: y=2x^2-10x-1 "for x="0" "rArry=-1 "for y="0 2x^2-10x-1=0 Delta=sqrt(100+4*2*1)" "Delta=sqrt(108)" "Delta=10,39 x_1=(10-10,39)/4 x_1=(0,39)/4 x_1=0,098 x_2=(10+10,39)/4 x_2=(20,39)/4 x_2=5,098 Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph y=x^2-2x+3? How do you know if y=16-4x^2 opens up or down? How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=0? See all questions in Quadratic Functions and Their Graphs Impact of this question 1554 views around the world You can reuse this answer Creative Commons License