What are the local extrema, if any, of $f(x)= x^2-1$ ?

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Answer 1 · 2015-12-03T02:07:53

$(0,-1)$

Local extrema occur when $f'(x)=0$ . So, find $f'(x)$ and set it equal to $0$ .

$f'(x)=2x$

$2x=0$

$x=0$

There is a local extremum at $(0,-1)$ .

Check a graph:

graph{x^2-1 [-10, 10, -5, 5]}

What are the local extrema, if any, of f(x)= x^2-1f(x)= x^2-1?