What are the local extrema of $f(x)=(x-1)/(x-4)$ ?

Question

1456 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-11T15:00:16

It has no local extrema

$f'(x) = -3/(x-4)^2$

$f'(x)$ is never $0$ and is undefined only at $x=4$ which is not in the domain of $f$ .

$f$ has no critical numbers, so $f$ has no local extrema.

What are the local extrema of f(x)=(x-1)/(x-4)f(x)=(x-1)/(x-4)?