What are the local extrema of f(x)= x^3-7x?

1 Answer
Dec 23, 2015

Turning points (local extrema) occur when the derivative of the function is zero,
ie when f'(x)=0.
that is when 3x^2-7=0
=>x=+-sqrt(7/3).

since the second derivative f''(x)=6x, and
f''(sqrt(7/3))>0 and f''(-sqrt(7/3))<0,

it implies that sqrt(7/3) is a relative minimum and -sqrt(7/3) is a relative maximum.

The corresponding y values may be found by substituting back into the original equation.

The graph of the function makes verifies the above calculations.

graph{x^3-7x [-16.01, 16.02, -8.01, 8]}