Question

What are the mean and standard deviation of a binomial probability distribution with `n=5` and `p=12/17`?

Answer 1

mean`~=3.529411765`
standard deviation`=1.018853416`

Explanation:

Mean `=np=5*12/17=60/17=3.529411765`

Standard deviation`=sqrt(npq)=sqrt(np(1-p))=sqrt(5(12/17)(1-12/17))=1.018853416`

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