What are the six trig function values of (19pi)/3? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Nov 4, 2015 Find the six trig functions of (19pi)/3 Explanation: sin ((19pi)/3) = sin (pi/3 + 6pi) = sin (pi/3) = sqrt3/2 cos ((19pi)/3) = cos (pi/3 + 6pi) = cos (pi/3) = 1/2 tan ((19pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3 cot ((19pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3 sec ((19pi)/3)= 1/(cos) = 2 csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3 Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 13438 views around the world You can reuse this answer Creative Commons License