What are the six trig function values of (19pi)/3?

1 Answer
Nov 4, 2015

Find the six trig functions of (19pi)/3

Explanation:

sin ((19pi)/3) = sin (pi/3 + 6pi) = sin (pi/3) = sqrt3/2
cos ((19pi)/3) = cos (pi/3 + 6pi) = cos (pi/3) = 1/2
tan ((19pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3
cot ((19pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3
sec ((19pi)/3)= 1/(cos) = 2
csc ((19pi)/3) = 1/(sin) = 2/sqrt3 = (2sqrt3)/3