Question

What are the six trig function values of `(-2pi)/3`?

Answer 1

Find six trig function values of `(-2pi)/3`

Explanation:

Call `(-2pi)/3 = x.`
Unit circle and Trig table of special arcs give -->
`sin x = sin (pi/3 - pi) = - sin (pi/3) = - 1/2`
`cos x = cos (pi/3 - pi) = - cos (pi/3) = -sqrt3/2`
`tan x = (-1/2)/(-sqrt3/2) = 1/sqrt3 = sqrt3`
`cot x = 1/sqrt3 = sqrt3/3`
`sec x = 1/(cos) = - 2/sqrt3 = -(2sqrt3)/3`
`csc x = 1/(sin) = -2`