What are the six trig function values of # (5pi)/3#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N May 17, 2018 Use trig table and unit circle --> #sin ((5pi)/3) = sin (-pi/3 + (6pi)/3) = sin (-pi/3) = - sin pi/3 = - sqrt3/2# #cos ((5pi)/3) = cos (-pi/3 + 2pi) = cos (-pi/3) = cos (pi/3) = 1/2# #tan ((5pi)/3) = sin/(cos) = (sqrt3/2)(2/1) = sqrt3# #cot ((5pi)/3) = 1/(tan) = 1/sqrt3 = sqrt3/3# #sec ((5pi)/3) = 1/(cos) = 2# #csc ((5pi)/3) = 1/(sin) = 2/sqrt3 = 2sqrt3/3# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 29016 views around the world You can reuse this answer Creative Commons License