(5pi)/6 has a reference angle of pi/6, so all its trig values will be related to the values for pi/6.
Also notice that (5pi)/6 is located in the second quadrant, so...
"SINE" will be positive.
"COSINE" will be negative.
sin(pi/6)=1/2, so color(blue)(sin((5pi)/6)=1/2.
cos(pi/6)=sqrt3/2, so color(blue)(cos((5pi)/6)=-sqrt3/2
"TANGENT" is just "SINE" divided by "COSINE":
color(blue)(tan((5pi)/6))=(1/2)/(-sqrt3/2)=1/2(-2sqrt3)=-1/sqrt3color(blue)(=-sqrt3/3
To figure out the other three, know that
"SECANT" is the reciprocal of "COSINE",
"COSECANT" is the reciprocal of "SINE", and
"COTANGENT" is the reciprocal of "TANGENT".
color(blue)(sec((5pi)/6))=1/(-sqrt3/2)=-2/sqrt3color(blue)(=-(2sqrt3)/3
color(blue)(csc((5pi)/6))=1/(1/2)color(blue)(=2
color(blue)(cot((5pi)/6))=1/(sqrt3/3)=3/sqrt3color(blue)(=sqrt3