What are the x intercepts for $f(x) = -2x^2 + 4x + 3$ ?

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Answer 1 · 2015-05-22T13:03:12

f(x) = -2x^2 + 4x + 3 = 0

$D = d^2 = b^2 - 4ac = 16 + 24 = 40 = 4(10) -> d = +- 2sqrt10$

Two x-intercepts: $x = -b/2a +- d/2a$

$x = 1 + (2sqrt10)/-4 = 1 - (sqrt10)/2$

$x = 1 + (sqrt10)/2$

What are the x intercepts for f(x) = -2x^2 + 4x + 3f(x) = -2x^2 + 4x + 3?