What are the x intercepts of ${(x + 4)}^{2} - 3 = 0$ $(x+4)^2-3=0$ ?

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What are the x intercepts of ${(x + 4)}^{2} - 3 = 0$ $(x+4)^2-3=0$ ?

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Answer 1 · 2018-07-11T13:37:36

$x = - 4 \pm \sqrt{3}$ $x=-4+-sqrt3$

Explanation:

$add 3 to both sides$ $"add 3 to both sides"$

${(x + 4)}^{2} = 3$ $(x+4)^2=3$

$take the square root of both sides$ $color(blue)"take the square root of both sides"$

$\sqrt{{(x + 4)}^{2}} = \pm \sqrt{3} \leftarrow note plus or minus$ $sqrt((x+4)^2)=+-sqrt3larrcolor(blue)"note plus or minus"$

$x + 4 = \pm 3$ $x+4=+-3$

$subtract 4 from both sides$ $"subtract 4 from both sides"$

$x = - 4 \pm \sqrt{3} \leftarrow exact values$ $x=-4+-sqrt3larrcolor(red)"exact values"$

$x \approx - 5.73 or x \approx - 2.27 to 2 dec. places$ $x~~-5.73" or "x~~-2.27" to 2 dec. places"$

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What are the x intercepts of ${(x + 4)}^{2} - 3 = 0$ $(x+4)^2-3=0$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

What are the x intercepts of (x+4)2−3=0(x+4)^2-3=0?

1 Answer

Explanation:

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Impact of this question

What are the x intercepts of ${(x + 4)}^{2} - 3 = 0$ $(x+4)^2-3=0$ ?