What are the zero(s) $4 x^{2} - 6 x + 13 = 0$ $4x^2-6x+13=0$ ?

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What are the zero(s) $4 x^{2} - 6 x + 13 = 0$ $4x^2-6x+13=0$ ?

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Answer 1 · 2015-10-25T17:23:12

Solve $y = 4 x^{2} - 6 x + 13 = 0$ $y = 4x^2 - 6x + 13 = 0$

Explanation:

$y = 4 x^{2} - 6 x + 13 .$ $y = 4x^2 - 6x + 13.$
$D = b^{2} - 4 a c = 36 - 208 < 0 .$ $D = b^2 - 4ac = 36 - 208 < 0.$
There are no real roots. The upward parabola doesn't intercept the x-axis.

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What are the zero(s) $4 x^{2} - 6 x + 13 = 0$ $4x^2-6x+13=0$ ?

1 Answer

Explanation:

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What are the zero(s) $4 x^{2} - 6 x + 13 = 0$ $4x^2-6x+13=0$ ?