What are the zeros of $f(x)= −4x^5 + 3$ ?

Question

5885 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-02-02T20:31:12

The answer is: $x=24^(1/5)/2$ .

It is sufficient to solve the system between the function and the line $y=0$ (x-axis).

So:

$-4x^5+3=0rArrx^5=3/4rArrx=""(3/4)^(1/5)=3^(1/5)/2^(2/5)=$
$=3^(1/5)/2^(2/5)*2^(3/5)/2^(3/5)=(3*2^3)^(1/5)/2=24^(1/5)/2$ .

What are the zeros of f(x)= −4x^5 + 3f(x)= −4x^5 + 3?