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What does pOH stand for?

1 Answer

May 9, 2016

This the base analogue of $p H$ $pH$ . $p O H$ $pOH$ $=$ $=$ $- {log}_{10} [H O^{-}]$ $-log_(10)[HO^-]$

Explanation:

In water, by definition, $p H + p O H = 14$ $pH + pOH =14$ .

And likewise for an aqueous acid, $p K_{a} + p K_{b} = 14$ $pK_a + pK_b =14$ .

So what is $p O H$ $pOH$ of a solution that is $0.10 \cdot m o l \cdot L^{- 1}$ $0.10*mol*L^-1$ with respect to $C a {(O H)}_{2}$ $Ca(OH)_2$ ?

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