What does $sec(arccos(2))+3cot(arctan(-1))$ equal?

Question

1453 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-12T12:32:30

As absolute value of cos x = |cos x| $<=1$ , there is no x for which cosine is 2.

If x = arc cos (2), cos x = 2 > 1.
So, arc cos(2) is unreal..

The second term = $3cot(arc cot(1/(-1))=3cot(arc cot(-1))=3(-1)=-3$

Successive operations by 'cot' over 'arc cot' amounts to multiplication by 1..

What does sec(arccos(2))+3cot(arctan(-1))sec(arccos(2))+3cot(arctan(-1)) equal?