Question

What four consecutive integers have a sum of 66?

Answer 1

Let the numbers be `x`, `x + 1`, `x + 2` and `x + 3`.

`x + x + 1 + x + 2 + x + 3 = 66`

`4x + 6 = 66`

`4x = 60`

`x = 15`

The numbers are therefore `15, 16, 17 and 18`.

Hopefully this helps!