Question

What is `5sintheta` in terms of `costheta`?

Answer 1

`5sin(theta) = +-5sqrt(1-cos(theta)^2)`

Explanation:

For the purpose of simplicity, i will replace sin(theta) with y and cos(theta) with x.

Let `sin(theta) = y` and `cos(theta)=x`
Recall `x^2+y^2=1`
`y^2=1-x^2`
`y=+-sqrt(1-x^2)`
`5y=+-5sqrt(1-x^2)`
Therefore:
`5sin(theta) = +-5sqrt(1-cos(theta)^2)`