What is $\frac{7 csc θ}{8}$ $(7csctheta)/8$ in terms of $cot θ$ $cottheta$ ?

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Answer 1 · 2018-03-17T11:24:07

$(\frac{7}{8}) \sqrt{1 + {cot}^{2} θ}$ $(7/8) sqrt(1 + cot^2 theta)$

${csc}^{2} θ = 1 + {cot}^{2} θ$ $csc^2 theta = 1 + cot^2 theta$

$csc θ = \sqrt{{cot}^{2} θ + 1}$ $csc theta = sqrt(cot^2 theta + 1)$

$\frac{7 csc θ}{8} = (\frac{7}{8}) \sqrt{1 + {cot}^{2} θ}$ $(7csc theta) / 8 = (7/8) sqrt(1 + cot^2 theta)$

What is 7cscθ8(7csctheta)/8 in terms of cotθcottheta?