What is $lim_(xrarroo) sin(x)/x$ ?

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Answer 1 · 2015-11-09T20:00:13

$lim_(xrarroo)sin(x)/x =0$

By the squeeze theorem

$AAx in RR :-1 <= sin(x) <= 1$

So $-1/x <= sin(x)/x<=1/x$

$lim_(xrarroo) -1/x = 0$

and

$lim_(xrarroo) 1/x = 0$

With the squeeze theorem we can say that

$sin(x)/x = 0$

What is lim_(xrarroo) sin(x)/x lim_(xrarroo) sin(x)/x ?