Question

What is molarity of K^+ in a solution that contains63.3ppm of K_3Fe(CN)_6.?(atomic masses are: K=39.1, Fe=56, C=12 , N=14)

Answer 1

Not high....

Explanation:

`"1 ppm"-=1*mg*L^-1`...and at these concentrations, we really do not have to consider solution density...

And so with respect to `K_3[Fe(C-=N)_6]`...we gots a concentration of `((63.3xx10^-3*g)/(329.24*g*mol^-1))/(1*L)=1.92xx10^-4*mol*L^-1`...

And so ...........

`[K^+]=3xx1.92xx10^-4*mol*L^-1=5.76xx10^-4*mol*L^-1`