What is the antiderivative of ln(1+x)? Calculus Techniques of Integration Integration by Parts 1 Answer Konstantinos Michailidis Mar 10, 2016 The antidervative is x*ln(1+x)-x+ln(1+x)+c Explanation: The antiderivative of ln(1+x) is the integral int ln(1+x)dx=int x' *ln(1+x)dx=x*ln(1+x)-int x/(1+x)dx= x*ln(1+x)-int[1-1/[1+x]]dx= x*ln(1+x)-x+ln(1+x)+c Answer link Related questions How do I find the integral int(x*ln(x))dx ? How do I find the integral int(cos(x)/e^x)dx ? How do I find the integral int(x*cos(5x))dx ? How do I find the integral int(x*e^-x)dx ? How do I find the integral int(x^2*sin(pix))dx ? How do I find the integral intln(2x+1)dx ? How do I find the integral intsin^-1(x)dx ? How do I find the integral intarctan(4x)dx ? How do I find the integral intx^5*ln(x)dx ? How do I find the integral intx*2^xdx ? See all questions in Integration by Parts Impact of this question 1740 views around the world You can reuse this answer Creative Commons License