What is the antiderivative of $lnx/x^2$ ?

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Answer 1 · 2016-09-11T01:55:16

If we take this to be integration by parts, then, let:

$u = lnx$
$du = 1/xdx$
$dv = 1/x^2dx$
$v = -1/x$

$uv - intvdu$

$= -(lnx)/x - (- int 1/x^2dx)$

$= color(blue)(-(lnx)/x - 1/x + C)$

What is the antiderivative of lnx/x^2 lnx/x^2?