What is the area of a hexagon where all sides are 8 cm?

1 Answer
Nov 27, 2015

Area =96sqrt(3) cm^2 or approximately 166.28 cm^2

Explanation:

A hexagon can be divided into 6 equilateral triangles. Each equilateral triangle can be further divided into 2 right triangles.

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Using the Pythagorean theorem, we can solve for the height of the triangle:

a^2+b^2=c^2

where:
a = height
b = base
c = hypotenuse

Substitute your known values to find the height of the right triangle:

a^2+b^2=c^2
a^2+(4)^2=(8)^2
a^2+16=64
a^2=64-16
a^2=48
a=sqrt(48)
a=4sqrt(3)

Using the height of the triangle, we can substitute the value into the formula for area of a triangle to find the area of the equilateral triangle:

Area_"triangle"=(base*height)/2

Area_"triangle"=((8)*(4sqrt(3)))/2

Area_"triangle"=(32sqrt(3))/2

Area_"triangle"=(2(16sqrt(3)))/(2(1))

Area_"triangle"=(color(red)cancelcolor(black)(2) (16sqrt(3)))/(color(red)cancelcolor(black)(2)(1))

Area_"triangle"=16sqrt(3)

Now that we have found the area for 1 equilateral triangle out of the 6 equilateral triangles in a hexagon, we multiply the area of the triangle by 6 to get the area of the hexagon:

Area_"hexagon"=6*(16sqrt(3))
Area_"hexagon"=96sqrt(3)

:., the area of the hexagon is 96sqrt(3) cm^2 or approximately 166.28 cm^2.