What is the area of a hexagon where all sides are 8 cm?
1 Answer
Area
Explanation:
A hexagon can be divided into
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Using the Pythagorean theorem, we can solve for the height of the triangle:
a^2+b^2=c^2
where:
a = height
b = base
c = hypotenuse
Substitute your known values to find the height of the right triangle:
a^2+b^2=c^2
a^2+(4)^2=(8)^2
a^2+16=64
a^2=64-16
a^2=48
a=sqrt(48)
a=4sqrt(3)
Using the height of the triangle, we can substitute the value into the formula for area of a triangle to find the area of the equilateral triangle:
Area_"triangle"=(base*height)/2
Area_"triangle"=((8)*(4sqrt(3)))/2
Area_"triangle"=(32sqrt(3))/2
Area_"triangle"=(2(16sqrt(3)))/(2(1))
Area_"triangle"=(color(red)cancelcolor(black)(2) (16sqrt(3)))/(color(red)cancelcolor(black)(2)(1))
Area_"triangle"=16sqrt(3)
Now that we have found the area for
Area_"hexagon"=6*(16sqrt(3))
Area_"hexagon"=96sqrt(3)