Question

What is the area of an isosceles triangle with a base of 6 and sides of 4?

Answer 1

The area of a triangle is `E=1/2 b*h` where b is the base and h is the height.
The height is `h=sqrt(a^2-(b/2)^2)=sqrt(4^2-3^2)=sqrt(16-9)=sqrt7`

So we have that `E=1/2 6 sqrt7=3*sqrt7=7.94`

Answer 2

I found `A=8`

Explanation:

Consider your triangle:

You can use Phytagoras Theorem to find `h` as:
`4^2=3^2+h^2`
`h=2.6`
So the area will be:
`A=1/2(basexxheight)=1/2(6xx2.6)=7.8~~8`