Question

What is the area under `f(x)=x^3-1` in `x in[0,1]`?

Answer 1

`3/4`

Explanation:

Area is `int_0^1(x^3-1)dx=((x^4)/4-x)`

`S=(1^4)/4-1-((0^4)/4-0)=-3/4`

"-" because curve is below the x-axis