What is the axis of symmetry and vertex for the graph $f(x) = -x^2 + 10$ ?

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Answer 1 · 2016-09-16T15:55:26

Vertex $(0,10)$

Axis of symetry $x=0$

Given -

$y=-x^2+10$

Let us rewrite it as -

$y=x^2+0x+10$

Vertex

X-Coordinate

$x=(-b)/(2a)=0/(2xx1)=0$

Y - Coordinate

$y=0^2+10$
$y=10$

Vertex $(0,10)$

Axis of symetry $x=0$

What is the axis of symmetry and vertex for the graph f(x) = -x^2 + 10f(x) = -x^2 + 10?