What is the axis of symmetry and vertex for the graph $f(x) = x^2 - 4x$ ?

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Answer 1 · 2016-03-02T12:17:13

Axis is x = 2 and vertex is (2, $-$ 4 )

The equation can be rearranged to the form
$( x-2 )^2$ = y + 4 = 4 x 1/4 X ( y + 4.)
The focus is at $( 2, -4+1/4 )$ = ( 2, $-$ 15/4 ).

What is the axis of symmetry and vertex for the graph f(x) = x^2 - 4xf(x) = x^2 - 4x?