What is the axis of symmetry and vertex for the graph $y = {(2 x)}^{2} - 12 x + 17$ $y=(2x)^2 - 12x + 17$ ?

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Answer 1 · 2016-03-20T12:13:38

Axis of symmetry $\to x = + \frac{3}{2}$ $->x= +3/2$

Write as $y = 4 x^{2} - 12 x + 17$ $" "y=4x^2-12x+17$

Now modify it as

$y = 4 (x^{2} - \frac{12}{4} x) + 17$ $y=4(x^2-12/4x)+17$

Axis of symmetry $\to x = (- \frac{1}{2}) \times (- \frac{12}{4}) = + \frac{3}{2}$ $->x=(-1/2)xx(-12/4) = +3/2$

What is the axis of symmetry and vertex for the graph y=(2x)2−12x+17y=(2x)^2 - 12x + 17?