What is the axis of symmetry and vertex for the graph y=3x^2-9?

1 Answer
Apr 16, 2016

Axis of symmetry ->x=0

Vertex ->(x,y)->(-9,0)

Explanation:

Consider the standard form of y=ax^2+bx+c

Given:" "y=3x^2-9

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color(blue)("General shape of the graph")

The three in front of x^2 is positive so the graph is of general shape uu. Suppose it was -3. Then the general shape for that scenario would be nn

So the shape of uu means we have a minimum.

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color(blue)("Axis of symmetry")

There is no term for the equation part bx thus the graphs axis of symmetry is x=0

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color(blue)("Vertex")

Suppose you just had color(brown)(y=3x^2) then the minimum would be at color(brown)(y=0)

However, we have color(brown)(y=3x^2)color(blue)( -9) so the vertex lowers by 9.

color(green)(y_("vertex")->color(brown)(y=0color(blue)(-9))=-9)

Tony B