What is the axis of symmetry and vertex for the graph #y= -4x^2#?

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Answer 1 · 2018-01-10T15:07:35

Axis of symmetry is #x=0# and vertex is #(0,0)#

When an equation #y=ax^2+bx+c# is converted in form

#y=a(x-h)^2+k#

axis of symmetry is #x-h=0# and vertex is #(h,k)#

As we can write #y=-4x^2#

as #y=-4(x-0)^2+0#

axis of symmetry is #x-0=0# i.e. #x=0# i.e. #y#-axis and vertex is #(0,0)#

graph{-4x^2 [-5.146, 4.854, -3.54, 1.46]}