What is the axis of symmetry and vertex for the graph $y = - 4 x^{2}$ $y= -4x^2$ ?

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Answer 1 · 2018-01-10T15:07:35

Axis of symmetry is $x = 0$ $x=0$ and vertex is $(0, 0)$ $(0,0)$

When an equation $y = a x^{2} + b x + c$ $y=ax^2+bx+c$ is converted in form

$y = a {(x - h)}^{2} + k$ $y=a(x-h)^2+k$

axis of symmetry is $x - h = 0$ $x-h=0$ and vertex is $(h, k)$ $(h,k)$

As we can write $y = - 4 x^{2}$ $y=-4x^2$

as $y = - 4 {(x - 0)}^{2} + 0$ $y=-4(x-0)^2+0$

axis of symmetry is $x - 0 = 0$ $x-0=0$ i.e. $x = 0$ $x=0$ i.e. $y$ $y$ -axis and vertex is $(0, 0)$ $(0,0)$

graph{-4x^2 [-5.146, 4.854, -3.54, 1.46]}

What is the axis of symmetry and vertex for the graph y=−4x2y= -4x^2?