Question

What is the axis of symmetry and vertex for the graph `y= -4x^2`?

Answer 1

Axis of symmetry is `x=0` and vertex is `(0,0)`

Explanation:

When an equation `y=ax^2+bx+c` is converted in form

`y=a(x-h)^2+k`

axis of symmetry is `x-h=0` and vertex is `(h,k)`

As we can write `y=-4x^2`

as `y=-4(x-0)^2+0`

axis of symmetry is `x-0=0` i.e. `x=0` i.e. `y`-axis and vertex is `(0,0)`

graph{-4x^2 [-5.146, 4.854, -3.54, 1.46]}