What is the axis of symmetry and vertex for the graph $y = - 7 x^{2} + 2 x$ $y= -7x^2 +2x$ ?

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What is the axis of symmetry and vertex for the graph $y = - 7 x^{2} + 2 x$ $y= -7x^2 +2x$ ?

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Answer 1 · 2018-07-07T13:14:21

$x = \frac{1}{7}, vertex = (\frac{1}{7}, \frac{1}{7})$ $x=1/7," vertex "=(1/7,1/7)$

Explanation:

$calculate the zeros by letting y = 0$ $"calculate the zeros by letting y = 0"$

$- 7 x^{2} + 2 x = 0$ $-7x^2+2x=0$

$x (- 7 x + 2) = 0$ $x(-7x+2)=0$

$x = 0, x = \frac{2}{7} \leftarrow are the zeros$ $x=0,x=2/7larrcolor(blue)"are the zeros"$

$the vertex lies on the axis of symmetry which is$ $"the vertex lies on the axis of symmetry which is"$
$situated at the midpoint of the zeros$ $"situated at the midpoint of the zeros"$

$axis of symmetry x = \frac{0 + \frac{2}{7}}{2} = \frac{1}{7}$ $"axis of symmetry "x=(0+2/7)/2=1/7$

$substitute this value into the equation for y-coordinate$ $"substitute this value into the equation for y-coordinate"$

$y = - 7 {(\frac{1}{7})}^{2} + 2 (\frac{1}{7}) = - \frac{1}{7} + \frac{2}{7} = \frac{1}{7}$ $y=-7(1/7)^2+2(1/7)=-1/7+2/7=1/7$

$vertex = (\frac{1}{7}, \frac{1}{7})$ $color(magenta)"vertex "=(1/7,1/7)$
graph{-7x^2+2x [-10, 10, -5, 5]}

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What is the axis of symmetry and vertex for the graph $y = - 7 x^{2} + 2 x$ $y= -7x^2 +2x$ ?

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Explanation:

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Science

Math

Humanities

... and beyond

What is the axis of symmetry and vertex for the graph y= -7x^2 +2xy=−7x2+2xy= -7x^2 +2x?

1 Answer

Explanation:

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Impact of this question

What is the axis of symmetry and vertex for the graph $y = - 7 x^{2} + 2 x$ $y= -7x^2 +2x$ ?