What is the axis of symmetry and vertex for the graph y = (x – 1)^2 – 16?

1 Answer
Jul 15, 2017

x=1" and "(1,-16)

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where ( h , k ) are the coordinates of the vertex and a is a constant.

y=(x-1)^2-16" is in this form"

"with " h=1" and " k=-16

rArrcolor(magenta)"vertex "=(1,-16)

"since " a>0" this graph opens up vertically"

"the axis of symmetry passes through the vertex"

"with equation "x=1