What is the axis of symmetry and vertex for the graph y = (x – 1)^2 – 16?
1 Answer
Jul 15, 2017
Explanation:
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where ( h , k ) are the coordinates of the vertex and a is a constant.
y=(x-1)^2-16" is in this form"
"with " h=1" and " k=-16
rArrcolor(magenta)"vertex "=(1,-16)
"since " a>0" this graph opens up vertically"
"the axis of symmetry passes through the vertex"
"with equation "x=1