What is the axis of symmetry and vertex for the graph y=x^2+3x-5?

1 Answer
Binayaka C.
Jul 31, 2016

Vertex at (-3/2,-29/4). Axis of symmetry is x= -3/2

Explanation:

y=x^2+3x-5 = (x+3/2)^2-9/4-5=(x+3/2)^2-29/4:.Comparing with general vertex form of equation y=a(x-h)^2+k we get vertex at (h,k) or (-3/2,-29/4).Axis of symmetry is x= -3/2 graph{x^2+3x-5 [-20, 20, -10, 10]} [Ans]

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