What is the axis of symmetry and vertex for the graph $y=x^2-7$ ?

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Answer 1 · 2017-07-03T16:24:29

Axis of symmetry is $x=0$ i.e. $y$ -axis and vertex is $(0,-7)$ .

A general equation of a parabola is $y=a(x-h)^2+k$ , where $(h,k)$ is the vertex and $x-h=0$ is the axis of symmetry.

Observe that we can write the given equation $y=x^2-7$ as

$y=1xx(x-0)^2-7$

and hence while axis of symmetry is $x=0$ i.e. $y$ -axis and vertex is $(0,-7)$ .

graph{(y-x^2+7)(x^2+(y+7)^2-0.02)=0 [-20, 20, -10, 10]}

What is the axis of symmetry and vertex for the graph y=x^2-7y=x^2-7?