What is the axis of symmetry and vertex for the graph y = x^2 -8x +10y=x28x+10?

1 Answer
Jun 26, 2017

Vertex is at (4,-6)(4,6) and the axis of symmetry is x=4x=4

Explanation:

y=x^2-8x+10 or y= (x-4)^2 -16+10y=x28x+10ory=(x4)216+10 or

y=(x-4)^2 -6y=(x4)26. Comparing with vertex form of equation

y=a(x-h)^2+k ; (h,k)y=a(xh)2+k;(h,k) being vertex, we find here

h=4 , k= -6h=4,k=6. Vertex is at (4,-6)(4,6) and the axis of symmetry is

x=4x=4
graph{x^2-8x+10 [-20, 20, -10, 10]} [Ans]