What is the axis of symmetry and vertex for the graph $y = x^{2} - 8 x + 10$ $y = x^2 -8x +10$ ?

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Answer 1 · 2017-06-26T10:13:23

Vertex is at $(4, - 6)$ $(4,-6)$ and the axis of symmetry is $x = 4$ $x=4$

$y = x^{2} - 8 x + 10 or y = {(x - 4)}^{2} - 16 + 10$ $y=x^2-8x+10 or y= (x-4)^2 -16+10$ or

$y = {(x - 4)}^{2} - 6$ $y=(x-4)^2 -6$ . Comparing with vertex form of equation

$y = a {(x - h)}^{2} + k; (h, k)$ $y=a(x-h)^2+k ; (h,k)$ being vertex, we find here

$h = 4, k = - 6$ $h=4 , k= -6$ . Vertex is at $(4, - 6)$ $(4,-6)$ and the axis of symmetry is

$x = 4$ $x=4$
graph{x^2-8x+10 [-20, 20, -10, 10]} [Ans]

What is the axis of symmetry and vertex for the graph y = x^2 -8x +10y=x2−8x+10y = x^2 -8x +10?