Question

What is the axis of symmetry for the graph `y=x^2-6x+2`?

Answer 1

`x=3`

Explanation:

The equation is written in the form `ax^2+bx+c`. As you can see, a=1, b=-6 and c=2. The axis of symmetry is worked out by `x=(-b)/(2a)`.

`(-(-6))/(2(1)` = `6/2 = 3`

Substituted this value of x back into the equation to find the y coordinate.

`y = (3)^2 -6(3) + 2`
`y = 9 -18+2`
`y = -7`

So the vertex of the line is at (3,-7)