What is the Cartesian form of $(- 1,(15pi )/3)$ ?

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Answer 1 · 2016-04-24T06:13:04

(x, y) = (1, 0)

Polar form $(r, theta) = (-1, 5pi)$ .

cos (odd multiple of $pi)=-1$ .

sin (any integer multiple of $pi)=0$

Cartesian form $(x, y)=(r cos theta, r sin theta)=(-cos 5pi, -sin 5pi)= (-(-1), 0)=(1, 0)$ ..

What is the Cartesian form of (- 1,(15pi )/3)(- 1,(15pi )/3)?