What is the Cartesian form of $(- 1, \frac{22 π}{4}))$ $(-1,(22pi)/4))$ ?

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What is the Cartesian form of $(- 1, \frac{22 π}{4}))$ $(-1,(22pi)/4))$ ?

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Answer 1 · 2017-02-02T18:45:06

(0,1)

Explanation:

First of all, angle $\frac{22 π}{4}$ $(22pi)/4$ is $\frac{11 π}{2}$ $(11pi)/2$ which is equivalent to $4 π + \frac{3 π}{2}$ $4pi +(3pi)/2$ that is $\frac{3 π}{2}$ $(3pi)/2$ because $4 π$ $4pi$ just adds 0 to the angle $\frac{3 π}{2}$ $(3pi)/2$

So, first we move by an angle of $\frac{3 π}{2}$ $(3pi)/2$ radians anti-clockwise
around the pole from starting position of 0 radians. This is shown in the figure below, as point P. Now since r= -1, we move in the opposite direction of r=1 for angle of $\frac{3 π}{2}$ $(3pi)/2$ . This positions has been indicated by point P' in the figure.

As is now evident from the figure, cartesean coordinates for $(- 1, \frac{22 π}{4})$ $(-1, (22pi)/4)$ would be point P' (0,1)

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What is the Cartesian form of $(- 1, \frac{22 π}{4}))$ $(-1,(22pi)/4))$ ?

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What is the Cartesian form of (−1,22π4))(-1,(22pi)/4))?

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What is the Cartesian form of $(- 1, \frac{22 π}{4}))$ $(-1,(22pi)/4))$ ?