Question

What is the Cartesian form of `( 1,(4pi )/3`?

Answer 1

`P=(-1/2,-sqrt3/2)`

Explanation:

`P=(r,theta)" in the polar form"`
`P=(x,y)=(r*cos theta,r*sin theta)" in Cartesian form"`
`P=(1*cos((4pi)/3),1*sin((4pi)/3))`
`P=(1*(-1/2),1*(-sqrt3/2))`

`P=(-1/2,-sqrt3/2)`