What is the Cartesian form of #(-10,(-17pi)/16))#?
1 Answer
Aug 8, 2017
Explanation:
We're asked to find the Cartesian (rectangular) form of a given polar coordinate.
To do this, we use the equations
#ul(x = rcostheta#
#ul(y = rsintheta#
In this case,
-
#r = -10# -
#theta = (-17pi)/16#
So we have
#x = -16cos((-17pi)/16) = ul(15.693#
#y = -16sin((-17pi)/16) = ul(-3.121#
The Cartesian coordinate is thus
#color(blue)(ulbar(|stackrel(" ")(" "(15.693, -3.121)" ")|)#