What is the Cartesian form of (-10,(-17pi)/16))?
1 Answer
Aug 8, 2017
Explanation:
We're asked to find the Cartesian (rectangular) form of a given polar coordinate.
To do this, we use the equations
ul(x = rcostheta
ul(y = rsintheta
In this case,
-
r = -10 -
theta = (-17pi)/16
So we have
x = -16cos((-17pi)/16) = ul(15.693
y = -16sin((-17pi)/16) = ul(-3.121
The Cartesian coordinate is thus
color(blue)(ulbar(|stackrel(" ")(" "(15.693, -3.121)" ")|)