What is the Cartesian form of $(10,(-7pi)/3))$ ?

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Answer 1 · 2016-05-10T11:23:07

$x=5$
$y=-5sqrt3$

The given data $(r, theta)=(10, (-7pi)/3)$

$x=r cos theta=10*cos ((-7pi)/3)=10*cos (-pi/3)=10*(1/2)$
$x=5$
$y=r sin theta+10*sin ((-7pi)/3)=10*sin (-pi/3)=10((-sqrt3)/2)$
$y=-5sqrt3$

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What is the Cartesian form of (10,(-7pi)/3))(10,(-7pi)/3))?