What is the Cartesian form of $( -12 , (13pi)/3 )$ ?

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Answer 1 · 2017-08-22T16:40:13

The Cartesian form is: $(-6,-6sqrt3)$

Use the conversion equations:

$x = rcos(theta)$ and $y = rsin(theta)$

$x = -12cos((13pi)/3)$ and $y = -12sin((13pi)/3)$

$x = -6$ and $y = -6sqrt3$

What is the Cartesian form of ( -12 , (13pi)/3 ) ( -12 , (13pi)/3 ) ?