What is the Cartesian form of $( -12 , ( 15pi)/4 )$ ?

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Answer 1 · 2017-03-28T18:45:35

$(-6sqrt(2), 6sqrt(2))$

Given: $( -12 , ( 15pi)/4 )$

Find the Cartesian form:

$(-12cos(( 15pi)/4 )), -12sin(( 15pi)/4 )) =$

$(-12sqrt(2)/2, -12(-sqrt(2)/2))$

$(-6sqrt(2), 6sqrt(2))$

What is the Cartesian form of ( -12 , ( 15pi)/4 ) ( -12 , ( 15pi)/4 ) ?