What is the Cartesian form of $(12,(-7pi)/3))$ ?

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Answer 1 · 2017-10-25T12:47:39

$(5 , -10.39 )$

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It can be seen from the diagram that the x coordinate of P is $rcos(theta)$ and the y coordinate of P is $rsin(theta)$

So:

$x=rcos(theta)$

$y=rsin(theta)$

From example:

$x=12cos((-7pi)/3)=-6$

$y=12sin((-7pi)/3)=-10.39$ (2 .d.p.)

Cartesian coordinate:

$(5 , -10.39 )$

What is the Cartesian form of (12,(-7pi)/3))(12,(-7pi)/3))?